Chapter 29: Parallel Resonance and Q factor

Date: 9/7/19

A parallel resonant circuit is usually used to establish a condition of stable frequency or current designed to produce an oscillation. In this circuit, a capacitor and inductor are connected directly together, exchanging energy with each other. They work in much the same way as a pendulum stabilizes the mechanical frequency of an oscillator circuit.

Another use is where a greatly increased impedance is desired at a certain frequency. They can be used to block a frequency range or to strain certain frequencies out of others. These circuits are called filters.

29.1 Parallel Network with Resistance, Pure Inductance, and Pure Capacitance

This is a parallel network containing resistance R, pure inductance L, and pure capacitance C connected in parallel. In a parallel circuit, we sum the admittances to get the overall admittance.

  • Admittance of the Resistor R is 1/R
  • Admittance of the inductor L is 1/(jXL) = -j/(ωL)
  • Admittance of the capacitor C is jωC

The total admittance Y is given by:

Y = 1/R + j(ωC – 1/ωL)

The circuit is resonant when ωrC – 1/(ωrL) = 0.

29.2 LR-C Parallel Network

This is a more practical network where the coil has inductance L and resistance R, and next to it (in parallel) is pure capacitance C. The admittances are:

  • Ycoil = 1/(R + jXL) = (R – jXL) / (R2 + XL2)
  • Yc = 1/(-jXc) = jωC

By summing the admittances and setting the imaginary part to zero, the equation to find the resonant frequency is derived as:

fr = (1 / 2π) √(1/LC – R2/L2)

When R2 / L2 is much less than 1/LC, then fr ≈ 1 / (2π√(LC)). The real part at resonance is a combination of resistance and inductance.

29.3 Dynamic Resistance

Since the current at resonance is in phase with the voltage, the impedance of the network acts as a resistance. This is known as the dynamic resistance (RD):

RD = V / Ir = L / (CR)

where Ir is the current at resonance.

29.4 LR-CR Parallel Network

In this network, Rc and RL are the resistances of the capacitor and coil respectively. Summing the admittances of the inductive and capacitive branches gives the total network admittance YT = Yc + YL. The resonant frequency equation emerges as:

fr = (1 / (2π√(LC))) × √((RL2 – L/C) / (Rc2 – L/C))

29.5 Q-factor in a Parallel Network

The Q-factor in a series R-L-C circuit is a measure of voltage magnification, whereas in a parallel network it is a measure of current magnification. As energy flows between the inductor and capacitor, circulating currents (Ic or IL) may be several times greater than the supply current at resonance.

Qr = Circulating Current / Current at Resonance = Ic / Ir

The Q-factor can be expressed as:

Qr = (ωrL) / Rt = (1/R) √(L/C)

The natural frequency fn is the frequency the loop would naturally resonate at, given by fn = 1 / (2π√(LC)). The relationship between the resonant (forced) frequency and natural frequency is:

fr = fn √(1 – 1/Q2)

Since Q is usually 10 or greater, the difference between fr and fn tends to be small. A high Q tends to make parallel and series resonant frequencies have the same value.

Bandwidth and Resonant Frequency

The expressions for Q-factor, bandwidth, and resonant frequency are similar to those in the series R-L-C circuit:

  • Qr = fr / (f2 – f1)
  • QT = (QLQc) / (QL + Qc)
  • fr = √(f1f2)

At the half-power frequencies, the impedance is Z = Zr / √2. The admittance relationship is Y / Yr = 1 + j2δQ, where δ is the fractional deviation from the resonant frequency.

29.6 Problems Re-started

Evaluating total admittance YT = Yc + YL:

Given Yc = 1 / (4 – j10) and YL = 1 / (3 + jXL)

Rationalizing the admittances:

  • Yc = (4 + j10) / (42 + 102) = (4 + j10) / 116
  • YL = (3 – jXL) / (32 + XL2)

At resonance, the imaginary parts of the admittances sum to zero:

10 / 116 = XL / (32 + XL2)

Cross multiplying gives:

10(9 + XL2) = 116XL
10XL2 – 116XL + 90 = 0

This quadratic equation can be solved using the standard formula XL = (-b ± √(b2 – 4ac)) / 2a.